A) \[{\scriptstyle{}^{1}/{}_{2}}\]sq. unit
B) \[1\] sq. unit
C) \[2\] sq. units
D) \[2\,\,{\scriptstyle{}^{1}/{}_{2}}\]sq. units
E) None of these
Correct Answer: E
Solution :
Given vertices of triangle are \[(2,\,\,3),(0,\,\,1)\] and \[(1,\,2)\] \[\therefore \] Area of triangle \[=\frac{1}{2}\left| \begin{matrix} 2 & 3 & 1 \\ 0 & 1 & 1 \\ 1 & 2 & 1 \\ \end{matrix} \right|\] \[=\frac{1}{2}[2(1-2(-3(-1)+1(0-1)]\] \[=\frac{1}{2}[2(-1)+3-1]\] \[=\frac{1}{2}[-2+3-1]=0\]
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