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J & K CET Engineering J and K - CET Engineering Solved Paper-2014

  • question_answer
    The ratio of magnitude of electric displacement  and electric field (E) is

    A)  charge density

    B)  permittivity

    C)  electric susceptibility

    D)  dielectric constant

    Correct Answer: B

    Solution :

    The dimension of electric displacement D = [Dimension of \[{{\varepsilon }_{0}}\]] [Dimension of E] So         \[\frac{[D]}{[E]}=\frac{[{{\varepsilon }_{0}}][E]}{[E]}=[{{\varepsilon }_{0}}]\] So,            \[\frac{D}{E}=\] Permittivity


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