A) \[0.1\]
B) \[0.01\]
C) \[0.2\]
D) \[0.02\]
Correct Answer: D
Solution :
So percentage change in length of wire \[=\frac{\Delta l}{l}\times 100%\] \[\frac{\Delta l}{l}\times \frac{2}{100}=0.02\]
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