A) \[46%\]
B) \[40%\]
C) \[30%\]
D) \[80%\]
Correct Answer: A
Solution :
\[Q\propto {{T}^{4}}\Rightarrow \frac{{{Q}_{1}}}{{{Q}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\] If \[{{T}_{1}}=T\] then \[{{T}_{2}}=T+\frac{10}{100}\,T=1.1\,T\] \[\frac{{{Q}_{1}}}{{{Q}_{2}}}={{\left( \frac{T}{1.1\,T} \right)}^{4}}\Rightarrow {{Q}_{2}}=1.46{{Q}_{1}}\] % increase in energy \[=\left( \frac{{{Q}_{2}}-{{Q}_{1}}}{{{Q}_{1}}} \right)%=46%\]
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