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J & K CET Engineering J and K - CET Engineering Solved Paper-2013

  • question_answer
    If  \[\left| \begin{matrix}    x+7 & 5  \\    x+-3 & 3  \\ \end{matrix} \right|=26,\] then x is equal to

    A)  \[1\]                   

    B)  \[3\]

    C)  \[5\]                   

    D)  \[7\]

    Correct Answer: C

    Solution :

    Given, \[\left| \begin{matrix}    x+7 & 5  \\    x-3 & 3  \\ \end{matrix} \right|=26\] \[\Rightarrow \] \[3(x+7)-5(x-3)=26\] \[\Rightarrow \] \[3x+21-5x+15=26\] \[\Rightarrow \] \[-2x+36=26\] \[\Rightarrow \] \[2x=10\] \[\Rightarrow \] \[x=5\]


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