A) \[0\]
B) \[1\]
C) \[cos\text{ }x\]
D) \[sin\text{ }x\]
Correct Answer: B
Solution :
\[\cos \left( \frac{3\pi }{2}+x \right)\cos (2\pi +x)\,\] \[\left\{ \cot \left( \frac{3\pi }{2}-x \right)\,+\cot \,(2\pi +x) \right\}\] \[=\sin x.\cos x\,(\tan \,x+\,\cot \,x\}\] \[=\sin x.\cos x\left( \frac{{{\sin }^{2}}x+{{\cos }^{2}}x}{\sin x.\cos x} \right)\] \[=1\] \[(\because \,\,\,{{\sin }^{2}}\theta +{{\cos }^{2}}\theta =1)\]
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