A) benzole acid
B) aniline
C) benzyl amine
D) benzonitrile
Correct Answer: C
Solution :
\[\underset{\text{benzoyl}\,\text{chloride}}{\mathop{{{C}_{6}}{{H}_{5}}COCl}}\,\xrightarrow[-HCl]{N{{H}_{3}}}\underset{\text{Benzamide}}{\mathop{{{C}_{6}}{{H}_{5}}CON{{H}_{2}}}}\,\] \[\xrightarrow[-{{H}_{2}}O]{{{P}_{2}}{{O}_{5}}}\underset{\text{benzonitrile}}{\mathop{{{C}_{6}}{{H}_{5}}CN}}\,\xrightarrow[{{H}_{2}}]{Ni}\underset{\text{benzylamine}}{\mathop{{{C}_{6}}{{H}_{5}}C{{H}_{2}}N{{H}_{2}}}}\,\]
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