A) \[N{{F}_{3}}\]
B) \[N{{H}_{3}}\]
C) \[C{{H}_{4}}\]
D) \[PC{{l}_{3}}\]
Correct Answer: B
Solution :
\[\text{N}{{\text{H}}_{\text{3}}}\]has the maximum dipole moment, i.e., 1.46 D. This is because. in case of \[\text{N}{{\text{H}}_{\text{3}}}\]the orbital dipole due to lone pairs is in the same direction as the resultant dipole moment of N?H bonds.
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