A) \[6.2\times {{10}^{-8}}\,m\]
B) \[7.25\times {{10}^{-8}}\,m\]
C) \[6.25\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) None of the above
Correct Answer: B
Solution :
According to de-Broglie equation \[\lambda =\frac{h}{mv}\] \[=\frac{6.6\times {{10}^{-34}}kg\,{{m}^{2}}{{s}^{-1}}}{9.1\times {{10}^{-31}}kg\times {{10}^{6}}m{{s}^{-1}}}\] \[=0.725\times {{10}^{-9}}m\] \[=7.25\times {{10}^{-10}}\,m\]
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