A) 24 g of magnesium
B) 12 got carbon
C) 24 got carbon
D) 12 g of magnesium
Correct Answer: D
Solution :
\[\because \]Number of atoms in 40 g of \[Ca=6.022\times {{10}^{23}}\] (Avogadro's number) \[\therefore \]Number of atoms in 20 g of Ca \[=\frac{6.022\times {{10}^{23}}\times 20}{40}=3.011\times {{10}^{23}}\] Like this \[\because \] Number of atoms in 24 g of Mg \[=6.022\text{ }\times {{10}^{23}}\] \[\therefore \]Number of atoms in 12 g of Mg \[=\frac{6.022\times {{10}^{23}}\times 12}{24}=3.011\times {{10}^{23}}\] Like this \[\because \]Number of atoms in 24 g of Mg \[=6.022\times {{10}^{23}}\] \[\therefore \]Number of atoms in 12 g of Mg \[=\frac{6.022\times {{10}^{23}}\times 12}{24}=3.011\times {{10}^{23}}\]
You need to login to perform this action.
You will be redirected in
3 sec
