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J & K CET Engineering J and K - CET Engineering Solved Paper-2013

  • question_answer
    The radioactive decay of thorium \[(A=232,\,\,Z=90)\] releases six alpha and four beta particles. The atomic number and mass number of the final product is                  

    A)  \[Z=80,\,\,A=207\]                                

    B)  \[Z=82,\,\,A=208\]                   

    C)  \[Z=92,\,\,A=209\]                           

    D)  \[Z=90,\,\,A=207\]                                   

    Correct Answer: B

    Solution :

    Decrease in mass number due to \[6\alpha =6\times 4=24\] Decrease in change number due to \[6\alpha =6\times 2=12\] Increase in change number due to four \[\beta =4\] \[\therefore \] Net mass number \[=232-24=208\] Net atomic number \[=90-12+4=82\]


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