2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2013

  • question_answer
    An electron revolves in a circle at the rate of 1019 rounds per second. The equivalent current is \[(e=1.6\times {{10}^{-19}}C)\]

    A)  \[1.0\,\,A\]            

    B)  \[1.6\,\,A\]

    C)  \[2.0\text{ }A\]            

    D)  \[2.6\text{ }A~\]

    Correct Answer: B

    Solution :

    Current \[I=ef\] Given, \[e=1.6\times {{10}^{-19}}C\] and \[f={{10}^{19}}\] \[\therefore \] \[I=1.6A\]


You need to login to perform this action.
You will be redirected in 3 sec spinner