A) \[1:1\]
B) \[1:2\]
C) \[1:3\]
D) \[1:4\]
Correct Answer: D
Solution :
Capacitor in series \[\frac{1}{{{C}_{s}}}=\frac{1}{C}+\frac{1}{C}=\frac{2}{C}\] \[\Rightarrow \] \[{{C}_{s}}=\frac{C}{2}\] Capacitor in parallel \[{{C}_{p}}=C+C=2C\] \[\therefore \]\[\frac{{{C}_{g}}}{{{C}_{p}}}=\frac{C}{2\times 2C}=\frac{1}{4}\]
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