J & K CET Engineering J and K - CET Engineering Solved Paper-2012

  • question_answer
    The real value of \[\theta \] for which the expression \[\frac{1+i\,\sin \theta }{1-2i\,\sin \theta }\] is a real number

    A)  \[2n\pi ,\], n is an integer

    B)  \[2n\pi +\frac{\pi }{2},\] n is an integer

    C)  \[2n\pi -\frac{\pi }{2},\] n is an integer

    D)  \[n\pi +\frac{\pi }{2},\] n is an integer

    Correct Answer: A

    Solution :

    Let \[z=\frac{1+i\sin \theta }{1-2i\,\sin \theta }\times \frac{1+2i\,\sin \theta }{1+2i\,\sin \theta }\] \[=\frac{1-2{{\sin }^{2}}\theta +3i\,(\sin \theta )}{1+4{{\sin }^{2}}\theta }\] For z to be real, \[3\,\sin \theta =0\] \[\Rightarrow \] \[\theta =n\pi \]


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