A) \[w\]
B) \[\frac{w}{2}\]
C) \[\frac{w}{4}\]
D) \[4\,w\]
Correct Answer: C
Solution :
The elastic limit of steel = support the maximum B load Load \[=Y\,\alpha \,\,\Delta t\pi {{r}^{2}}\] Then, \[w=Y\pi \,\alpha \,\Delta t{{R}^{2}}\] ...(i) load \[=Y\pi \,\alpha \,\,\Delta t{{\left( \frac{R}{2} \right)}^{2}}\] \[=\frac{y\pi \,\alpha \,\Delta t{{R}^{2}}}{4}=\frac{\omega }{4}\]
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