J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer
    The degree of the differential equation  \[\frac{{{d}^{2}}y}{d{{x}^{2}}}=\frac{5y+\frac{dy}{dx}}{\sqrt{\frac{{{d}^{2}}y}{d{{x}^{2}}}}}\]is equal to

    A)  \[2\]     

    B)  \[3\]

    C)  \[4\]   

    D)  \[5/2\]

    Correct Answer: B

    Solution :

    \[\frac{{{d}^{2}}y}{d{{x}^{2}}}=\frac{5y+\frac{dy}{dx}}{\sqrt{{{d}^{2}}y/d{{x}^{2}}}}\] \[{{\left( \frac{{{d}^{2}}y}{d{{x}^{2}}} \right)}^{3/2}}=5y+\frac{dy}{dx}\] Squaring on both sides, \[{{\left( \frac{{{d}^{2}}y}{d{{x}^{2}}} \right)}^{3}}={{\left( 5y+\frac{dy}{dx} \right)}^{2}}\] So, the degree of given differential equation is 3.


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