J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer
    A particle is thrown vertically upwards with velocity \[24.5\text{ }cm/min\]. It will return to the original position after

    A)  \[1\,s\]           

    B)  \[3\,\,s\]

    C)  \[1.5\,\,s\]          

    D)  None of these

    Correct Answer: D

    Solution :

    The initial velocity of the particle is \[u=24.5\,\,cm/\min \] \[u=\frac{24.5}{100}\times \frac{1}{60}m/s\] The total time \[T=\frac{2u}{g}=\frac{2\times 24.5}{600\times 9.8}=\frac{1}{120}s\]


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