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J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer
    The equation of the plane perpendicular to the Z-axis and passing through \[(2,-3,5)\] is

    A)  \[x-2=0\]

    B)  \[y+3=0\]

    C)  \[z-5=0\]

    D)  \[2x-3y+5z+4=0\]

    Correct Answer: C

    Solution :

    Since, the plane perpendicular to z-axis, so the normal of the plane is parallel to z-axis, the direction cosine?s of z-axis is \[(0,0,1)\]. Then, the equation of plane which passes through the point \[(3,-3,5)\] and perpendicular to z-axis is \[0(x-2)+0(y+3)+1(z-5)=0\] \[\Rightarrow \] \[z-5=0\]


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