J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer
    When 'blue vitriol? is heated at 373 K, the product formed is

    A) \[CuS{{O}_{4}}.3{{H}_{2}}O\]

    B) \[CuO+S{{O}_{3}}\]

    C)  \[CuS{{O}_{4}}.{{H}_{2}}O\]

    D) \[CuS{{O}_{4}}\]

    Correct Answer: C

    Solution :

     \[\underset{\text{blue}\,\text{vitriol}}{\mathop{CuS{{O}_{4}}.5{{H}_{2}}O}}\,\xrightarrow[-4{{H}_{2}}O]{373\,K}\underset{\text{bluish}\,\text{white}}{\mathop{CuS{{O}_{4}}.{{H}_{2}}O}}\,\xrightarrow[-{{H}_{2}}O]{503\,K}\] \[\underset{\text{white}}{\mathop{CuS{{O}_{4}}}}\,\xrightarrow{1023\,K}CuO+\underbrace{S{{O}_{2}}+{{O}_{2}}}_{S{{O}_{3}}}\]


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