A) \[2S{{O}_{2}}(g)+{{O}_{2}}(g)2S{{O}_{3}}(g)\]
B) \[{{N}_{2}}(g)+3{{H}_{2}}(g)2N{{H}_{3}}(g)\]
C) \[PC{{l}_{5}}(g)PC{{l}_{3}}(g)+C{{l}_{2}}(g)\]
D) \[{{N}_{2}}(g)+{{O}_{2}}(g)2NO(g)\]
Correct Answer: C
Solution :
If \[\Delta n>0,\]the increase in pressure favours backward reaction and therefore the yield of the products decreases. \[PC{{l}_{5}}(g)PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] Here, An > 0, hence the yield of the products decreases by increasing the pressure.
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