A) 1
B) 2
C) 0
D) 3
Correct Answer: B
Solution :
The electronic configuration of\[{{\text{C}}_{\text{2}}}\] molecule is as \[{{\text{C}}_{2}}=\sigma 1{{s}^{2}},{{\sigma }^{*}}1{{s}^{2}},\sigma 2{{s}^{2}},{{\sigma }^{*}}2{{s}^{2}},\pi 2p_{y}^{2}=\pi 2p_{z}^{2}\] \[\text{Bond}\,\text{order}=\frac{{{N}_{b}}-{{N}_{a}}}{2}\] \[=\frac{8-4}{2}\] \[=2\]
You need to login to perform this action.
You will be redirected in
3 sec
