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J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer
    The escape velocity of a body on the surface of earth is \[11.2\text{ }km/s\]. If the earth's mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become

    A)  \[5.6\,\,km/s\]

    B)  \[11.2\,\,km/s\]

    C)  \[44.8\,\,km/s\]

    D)  \[22.4\,\,km/s\]

    Correct Answer: D

    Solution :

    Escape velocity, \[{{v}_{e}}=\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2G\times 2M}{R/2}}\] \[=2\sqrt{\frac{2GM}{R}}=2\times 11.2km/s\] \[=22.4km/s\]


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