A) \[\frac{{{C}_{1}}V}{{{C}_{1}}+{{C}_{2}}}\]
B) \[\frac{{{C}_{2}}V}{{{C}_{1}}+{{C}_{2}}}\]
C) \[1+\frac{{{C}_{2}}}{{{C}_{1}}}\]
D) \[1-\frac{{{C}_{2}}}{{{C}_{1}}}\]
Correct Answer: A
Solution :
If two capacitors having capacitance \[{{C}_{1}}\] and \[{{C}_{2}}\] respectively are connected in parallel, then \[{{C}_{eq}}={{C}_{1}}+{{C}_{2}}\] The final potential difference across each capacitor \[V'=\frac{{{C}_{1}}V}{{{C}_{1}}+{{C}_{2}}}\]
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