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J & K CET Engineering J and K - CET Engineering Solved Paper-2011

  • question_answer
    A 100 turn closely wound circular coil of radius \[10\text{ }cm\]carries a current of \[3.2\text{ }A\]. The magnetic   moment  of  the   coil is, approximately

    A)  \[5\text{ }A{{m}^{2}}\]       

    B)  \[10\text{ }A{{m}^{2}}\]

    C)  \[20\text{ }A{{m}^{2}}\]       

    D)  \[40\text{ }A{{m}^{2}}\]

    Correct Answer: A

    Solution :

    Magnetic moment, \[M=niA\] \[M=100\times 3.2\times (\pi r_{1}^{2})\] \[=100\times 3.2\times \frac{22}{7}\times \frac{10}{100}\times \frac{10}{100}\] \[=10.048\,A-{{m}^{2}}\]


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