A) \[p\to n+{{e}^{+}}+v\]
B) \[n\to p+{{e}^{-}}+\bar{v}\]
C) \[n\to p+{{e}^{+}}+\bar{v}\]
D) \[n\to p+{{e}^{+}}+v\]
Correct Answer: C
Solution :
A beta minus particle \[{{\beta }^{-}}\] is an electron. Emission of \[{{\beta }^{-}}\] involves transformation of a neutron into a proton, an electron and a third particle called an antineutrino. \[n=p{{+}_{-1}}{{\beta }^{0}}+\bar{v}\] or \[n\to p+{{e}^{-}}+\bar{v}\]
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