A) \[2n\pi \pm \frac{\pi }{3},n\in Z\]
B) \[n\pi \pm \frac{\pi }{6},n\in Z\]
C) \[n\pi \pm \frac{\pi }{2},n\in Z\]
D) \[2n\pi \pm \frac{\pi }{6},n\in Z\]
Correct Answer: B
Solution :
Given, \[{{\cot }^{2}}\theta =3\] \[\Rightarrow \] \[{{\tan }^{2}}\theta =\frac{1}{3}\] \[\Rightarrow \] \[\tan \theta =\pm \frac{1}{\sqrt{3}}\] \[\Rightarrow \] \[\theta =n\pi \pm \frac{\pi }{6},\,\,\,\,n\in Z\]
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