J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    Which one of the following is not true for the function \[f(x)={{x}^{2}}-x+1,\,0\le x\le 1\]?

    A)  Increases on \[\left[ \frac{1}{2},1 \right]\]

    B)  Decreases on \[\left[ 0,\frac{1}{2} \right]\]

    C)  Increases on \[\left[ 0,\frac{1}{2} \right]\]

    D)  Neither increases nor decreases on \[[0,\,\,1]\]

    Correct Answer: C

    Solution :

    Given function \[f(x)={{x}^{2}}-x+1,0\le x\le 1\] For strictly increasing function \[f'(x)>0\] \[2x-1>0\] \[x>\frac{1}{2}\] Hence, function is not increasing in\[\left[ 0,\frac{1}{2} \right]\].


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