J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    The foot of the perpendicular drawn from the origin to a plane is \[(1,-1,5)\]. The equation of the plane is

    A)  \[\vec{r}.(\hat{i}-\hat{j}+5\hat{k})=27\]

    B)  \[\vec{r}.(\hat{i}-\hat{j}+5\hat{k})=\sqrt{27}\]

    C)  \[\vec{r}.(5\hat{i}-\hat{j}+\hat{k})=\frac{1}{\sqrt{27}}\]

    D)  \[x-y-5z-27=0\]

    Correct Answer: A

    Solution :

    Here,   \[\vec{n}=\hat{i}-\hat{j}+5\hat{k}\] \[\hat{n}=\frac{{\vec{n}}}{|\vec{n}|}=\frac{\hat{i}-\hat{j}+5\hat{k}}{\sqrt{{{(1)}^{2}}+{{(-1)}^{2}}+{{(5)}^{2}}}}\] \[\frac{\hat{i}-\hat{j}+5\hat{k}}{\sqrt{27}}\] Also, length of perpendicular from origin to the plane is \[d=\sqrt{{{(1)}^{2}}+{{(-1)}^{2}}+{{(5)}^{2}}}=\sqrt{27}\] Now, equation of plane \[\vec{r}.\hat{n}=d\] \[\vec{r}.\,\frac{(\hat{i}-\hat{j}+5\hat{k})}{\sqrt{27}}=\sqrt{27}\] \[\Rightarrow \] \[\vec{r}.\,(\hat{i}-\hat{j}+5\hat{k})=27\]


You need to login to perform this action.
You will be redirected in 3 sec spinner