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J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    36 g of glucose (molar mass\[=180\text{ }g/mol\]) if present in 500 g of water, the molality of the solution is

    A)  0.2               

    B)  0.4

    C)  0.8               

    D)  1.0

    Correct Answer: B

    Solution :

     Molality,\[\text{m}\,\text{=}\,\frac{\text{moles}\,\text{of}\,\text{solute}\,\text{ }\!\!\times\!\!\text{ 1000}}{\text{mass}\,\text{of}\,\text{solvent}\,\text{(in}\,\text{g)}}\] \[=\frac{36\times 1000}{180\times 500}=0.4\,m\]


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