A) lowering of vapour pressure is equal to the mole fraction of the solute
B) relative lowering of vapour pressure is equal to the mole fraction of the solvent
C) relative lowering of vapour pressure of the solvent is equal to the mole fraction of the solute
D) vapour pressure of the solution is equal to the vapour pressure of the solvent
Correct Answer: C
Solution :
Raoult's law states that the relative lowering of vapour pressure of the solvent is equal to the mole fraction of the solute, \[ie,\] \[\frac{{{p}^{o}}-{{p}_{s}}}{{{p}^{o}}}={{\chi }_{s}}\] (where,\[{{p}^{o}}-{{p}_{s}}=\]lowering in vapour pressure,\[{{\chi }_{s}}=\] mole fraction of solute)
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