A) \[n-4\] \[l-3\] \[m-2\] \[s-\,\,\,\,\,\text{-1/2}\]
B) \[n-4\] \[l-2\] \[m-0\] \[s-\,\,\,\,\,\text{-1/2}\]
C) \[n-4\] \[l-1\] \[m-0\] \[s-\,\,\,\,\,+\text{1/2}\]
D) \[n-4\] \[l-0\] \[m-0\] \[s-\,\,\,\,\,\text{-1/2}\]
Correct Answer: D
Solution :
The electronic configuration of potassium is \[{{\,}_{19}}K=1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},4{{s}^{1}}\] For \[4{{s}^{1}},\] \[n=4\] \[l=0\] (\[\because \]for s orbital,\[l=0\]) \[m=0\] \[s=-\frac{1}{2}\]
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