A) \[\frac{Q}{6\,{{\varepsilon }_{0}}}\]
B) \[\frac{Q}{4\,{{\varepsilon }_{0}}}\]
C) \[\frac{Q}{8\,{{\varepsilon }_{0}}}\]
D) \[\frac{Q}{\,{{\varepsilon }_{0}}}\]
Correct Answer: B
Solution :
According to Gauss's theorem \[\phi =\frac{q}{{{\varepsilon }_{0}}}\] or \[E.2\pi R\times l=\frac{\lambda }{{{\varepsilon }_{0}}}\] \[\Rightarrow \] \[E=\frac{1}{2\pi }\frac{\lambda }{{{\varepsilon }_{0}}(R/2)}\times 2\] \[(l=1)\] \[=\frac{2\lambda }{\pi {{\varepsilon }_{0}}R}\]
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