A) \[x=1;\,\,y=2\]
B) \[x=2;\,\,y=1\]
C) \[x=\frac{1}{3};\,\,y=\frac{2}{3}\]
D) \[x=\frac{2}{3};\,\,y=\frac{1}{3}\]
E) None of these
Correct Answer: E
Solution :
\[{{x}_{CM}}=\frac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}}{{{m}_{1}}+{{m}_{2}}};\,\,{{y}_{CM}}=\frac{{{m}_{1}}{{y}_{1}}+{{m}_{2}}{{y}_{2}}}{{{m}_{1}}+{{m}_{2}}}\] \[=\frac{1\times 0+2\times 1}{3}=\frac{2}{3};y=\frac{1\times 0+2\times 0}{3}=0\] \[\left[ \frac{2}{3},0 \right]\] Hence, no option is correct.
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