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J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    The Brewster angle for the glass-air interface is \[{{54.74}^{o}}\]. if a ray of light going from air to glass strikes at an angle of incidence \[{{45}^{o}},\] then the angle of refraction is (Given, tan\[{{54.74}^{o}}=\sqrt{2}\])

    A)  \[{{60}^{o}}\]           

    B)  \[{{30}^{o}}\]

    C)  \[{{25}^{o}}\]             

    D)  \[{{54.74}^{o}}\]

    Correct Answer: B

    Solution :

    Refractive index, \[\mu =\tan \theta =\sqrt{2}\] Now according to Snell?s law \[\sqrt{2}=\frac{\sin \,(54.74)}{\sin r}\] \[\sin \,r=\frac{0.816}{\sqrt{2}}\] \[\sin \,r=0.57\] \[r={{35}^{o}}\simeq {{30}^{o}}\]


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