J & K CET Engineering J and K - CET Engineering Solved Paper-2010

  • question_answer
    If the radius of a nucleus of mass number 3 is R, ,then the radius of a nucleus of mass number 81 is

    A)  \[3\,R\]          

    B)  \[9\,R\]

    C)  \[{{(27)}^{1/2}}\,R\]       

    D)  \[27\text{ }R\]

    Correct Answer: A

    Solution :

    Nuclear radius is proportional to \[{{A}^{1/3}}\] where, A is mass number of nucleus. ie,            \[R\propto {{A}^{1/3}}\] \[\frac{{{R}_{1}}}{{{R}_{2}}}={{\left[ \frac{{{A}_{1}}}{{{A}_{2}}} \right]}^{1/3}}\] \[\frac{R}{{{R}_{2}}}={{\left[ \frac{3}{81} \right]}^{1/3}}\] or \[\frac{R}{{{R}_{2}}}=\frac{1}{3}\] or \[{{R}_{2}}=3R\]


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