A) \[\frac{4}{9}\]
B) \[\frac{5}{8}\]
C) \[\frac{5}{9}\]
D) \[\frac{5}{12}\]
Correct Answer: A
Solution :
Total number of ways \[{{=}^{9}}{{C}_{2}}\] Required probability \[=\frac{^{5}{{C}_{2}}{{\times }^{4}}{{C}_{0}}}{^{9}{{C}_{2}}}+\frac{^{5}{{C}_{0}}{{\times }^{4}}{{C}_{2}}}{^{9}{{C}_{2}}}\] \[=\frac{5\times 4}{9\times 8}+\frac{4\times 3}{9\times 8}=\frac{32}{9\times 8}\] \[=\frac{4}{9}\]
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