J & K CET Engineering J and K - CET Engineering Solved Paper-2009

  • question_answer
    In    \[\Delta \,\,ABC,\]if \[s=\frac{a+b+c}{2},\]then \[\left( b\,\,{{\cos }^{2}}\,\frac{C}{2}+c\,\,{{\cos }^{2}}\,\frac{B}{2} \right)\] is equal to

    A)  \[s\]

    B)  \[2s\]

    C)  \[4\,s\]               

    D)  \[3\,s\]

    Correct Answer: A

    Solution :

    \[b\,{{\cos }^{2}}\frac{C}{2}+c\,{{\cos }^{2}}\frac{B}{2}\] \[=b{{\left( \sqrt{\frac{s(s-c)}{ab}} \right)}^{2}}+c{{\left( \sqrt{\frac{s(s-b)}{ca}} \right)}^{2}}\] \[=b\left( \frac{s(s-c)}{ab} \right)+c\left( \frac{s(s-b)}{ca} \right)\] \[=\frac{{{s}^{2}}-sc+{{s}^{2}}-sb}{a}=\frac{2{{s}^{2}}-s(b+c)}{a}\] \[=\frac{2{{s}^{2}}-s(2s-a)}{a}\] \[=\frac{2{{s}^{2}}-2{{s}^{2}}+sa}{a}=s\]


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