J & K CET Engineering J and K - CET Engineering Solved Paper-2009

  • question_answer
    The number of molecules in 18 mg of water in terms of Avogadro number N is

    A)  \[{{10}^{-3}}N\]

    B) \[{{10}^{-2}}N\]

    C)  \[{{10}^{-1}}N\]

    D) \[10N\]

    Correct Answer: A

    Solution :

     Given, weight of water \[=18\,mg=18\times {{10}^{-3}}g\] \[\therefore \]Number of moles \[=\frac{\text{weight}}{\text{molar}\,\text{mass}}\] \[=\frac{18\times {{10}^{-3}}}{18}=1\times {{10}^{-3}}\] and number of molecules = no. of moles \[\times \] Avogadro number. \[=\,1\times {{10}^{-3}}\times N\] \[={{10}^{-3}}N.\]


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