J & K CET Engineering J and K - CET Engineering Solved Paper-2009

  • question_answer
    If the photoelectric work function for a metallic surface is \[4.125\text{ }eV,\]the cut-off wavelength for photoelectric phenomenon for the surface is

    A)  \[4500\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]        

    B)  \[1700\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]

    C)  \[2800\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]        

    D)  \[3000\text{ }\overset{\text{o}}{\mathop{\text{A}}}\,\]

    Correct Answer: D

    Solution :

    As \[E(eV)=\frac{12375}{\lambda (\overset{\text{o}}{\mathop{\text{A}}}\,)}\] \[4.125=\frac{12375}{\lambda }\] \[\lambda =\frac{12375}{4.125}\] \[=3000\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]


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