question_answer

Heater coil A takes \[{{t}_{1}}\] second to boil certain quantity of water. Heater coil B takes 13 second to boil same quantity of water. If A and B are connected in series, the time taken to boil the same quantity of water by the combination is

A)  \[-\frac{1}{\sqrt{2}},\frac{1}{\sqrt{2}},\frac{1}{2}\]

B)  \[\frac{1}{\sqrt{2}},-\frac{1}{2},\frac{1}{2}\]

C)  \[-\frac{1}{2},\frac{1}{\sqrt{2}},\frac{1}{2}\]

D)  \[\frac{1}{2},\frac{1}{\sqrt{2}},\frac{1}{2}\]