A) \[\frac{Y}{2}\]
B) \[2Y\]
C) \[Y\]
D) \[4\,y\]
Correct Answer: A
Solution :
Young's modulus \[Y=\frac{stress}{strain}\] \[Y=\frac{FL}{Al}\] \[\therefore \] \[Y\propto \frac{1}{l}\] \[\Rightarrow \] \[\frac{{{Y}_{1}}}{{{Y}_{2}}}=\frac{{{l}_{2}}}{{{l}_{1}}}\] or \[\frac{Y}{{{Y}_{2}}}=\frac{2l}{l}\] \[\Rightarrow \] \[{{Y}_{2}}=\frac{Y}{2}\]
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