J & K CET Engineering J and K - CET Engineering Solved Paper-2008

  • question_answer
    \[3a{{\int_{0}^{1}{\left( \frac{ax-1}{a-1} \right)}}^{2}}\,\,dx\]is equal to

    A)  \[a-1+{{(a-1)}^{-2}}\]

    B)  \[a+{{a}^{-2}}\]

    C)  \[a-{{a}^{-2}}\]

    D)  \[{{a}^{2}}+\frac{1}{{{a}^{2}}}\]

    Correct Answer: A

    Solution :

    \[3a\int_{0}^{1}{{{\left( \frac{ax-1}{a-1} \right)}^{2}}\,dx=\frac{3a}{{{(a-1)}^{2}}}}\left[ \frac{{{(ax-1)}^{3}}}{3}\times \frac{1}{a} \right]_{0}^{1}\] \[=\frac{1}{{{(a-1)}^{2}}}[{{(a-1)}^{3}}+1]\] \[=(a-1)+{{(a-1)}^{-2}}\]


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