2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2008

  • question_answer
    \[\tan {{25}^{o}}+\tan {{20}^{o}}+\tan {{25}^{o}}\,\tan {{20}^{o}}\] is equal to

    A)  \[1\]              

    B)  \[2\]

    C)  \[3\]              

    D)  \[4\]

    Correct Answer: A

    Solution :

    Now, \[\tan {{45}^{o}}=\tan ({{25}^{o}}+{{20}^{o}})\]--- \[\Rightarrow \] \[1=\frac{\tan {{25}^{o}}+\tan {{20}^{o}}}{1-\tan {{25}^{o}}\,\tan \,{{20}^{o}}}\] \[\Rightarrow \] \[\tan {{25}^{o}}+\tan {{20}^{o}}+\tan {{25}^{o}}\tan {{20}^{o}}=1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner