A) 8
B) 10
C) 6.96
D) 12
Correct Answer: C
Solution :
If the concentration of acid is less than \[{{10}^{-7}},\] then the concentration of \[{{\text{H}}^{\text{+}}}\]present in water is not neglected. Total \[[{{H}^{+}}]=[{{H}^{+}}]\]from \[HCl+[{{H}^{+}}]\]\[{{H}_{2}}O\] \[={{10}^{-8}}+{{10}^{-7}}\] \[={{10}^{-7}}(1.1)\] \[=1.1\times {{10}^{-7}}\,\text{mol/L}\] \[pH=-\log [{{H}^{+}}]\] \[=-\log (1.1\,\times \,{{10}^{-7}})\] \[=6.96\]
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