A) \[{{K}_{p}}\ne {{K}_{c}}\]
B) \[{{K}_{p}}={{K}_{c}}\]
C) \[{{K}_{p}}>{{K}_{c}}\]
D) \[{{K}_{p}}<{{K}_{c}}\]
Correct Answer: B
Solution :
\[{{H}_{2}}(g)+C{{l}_{2}}(g)2HCl(g)\] We know that, \[{{K}_{p}}={{K}_{c}}.{{(RT)}^{\Delta {{n}_{g}}}}\] \[\Delta {{n}_{g}}=\]no. of moles of gaseous products - no. of moles of gaseous reactants \[=2-2=0\] \[{{K}_{p}}={{K}_{c}}.{{(RT)}^{o}}\] \[{{K}_{p}}={{K}_{c}}\]
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