2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2008

  • question_answer
    A body is under the action of two mutually perpendicular forces of \[3\text{ }N\]and\[4\text{ }N\]. The resultant force acting on the body is

    A) \[7\,N\]           

    B)  \[1\,N\]

    C)  \[5\,N\]            

    D)  zero

    Correct Answer: C

    Solution :

    Resultant force, \[F=\sqrt{F_{1}^{2}+F_{2}^{2}+2{{F}_{1}}{{F}_{2}}\,\,\cos \,\theta }\] \[=\sqrt{{{(3)}^{2}}+{{(4)}^{2}}+2\times 3\times 4\,\cos \,{{90}^{o}}}\] \[=5N\]


You need to login to perform this action.
You will be redirected in 3 sec spinner