2. Solved Papers
  3. J & K CET Engineering

J & K CET Engineering J and K - CET Engineering Solved Paper-2007

  • question_answer
    If A and B are mutually exclusive events with \[P(A)=\frac{1}{2}\times P(B)\] and \[A\cup B=S,\] (total sample space) then \[P(A)\] is equal to

    A)  \[\frac{2}{3}\]

    B)  \[\frac{1}{3}\]

    C)  \[\frac{1}{4}\]

    D)  \[\frac{3}{4}\]

    Correct Answer: B

    Solution :

    Given,    \[P(A)=\frac{1}{2}P(B)\] \[\Rightarrow \] \[P(B)=2P(A)\] and \[A\cup B=S\] \[\therefore \] \[P(A\cup B)=P(S)=1\] \[\Rightarrow \] \[P(A)+P(B)=1\]\[[\because \,\,P(A\cap B)=0]\] \[\Rightarrow \] \[P(A)+2P(A)=1\] \[\Rightarrow \] \[P(A)=\frac{1}{3}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner