J & K CET Engineering J and K - CET Engineering Solved Paper-2007

  • question_answer
    If \[P=(0,1,2),\,\,Q=(4,-2,1),O=(0,0,0),\] then \[\angle POQ\] is equal to

    A)  \[\frac{\pi }{6}\]

    B)  \[\frac{\pi }{4}\]

    C)  \[\frac{\pi }{3}\]

    D)  \[\frac{\pi }{2}\]

    Correct Answer: D

    Solution :

    Direction ratios of \[OP=(0-0,\,1-0,\,\,2-0)=(0,1,2)\] Direction ratios of \[OQ=(4-0,-2-0,1-0)=(4,-2,1)\] Let \[\angle POQ=\theta ,\]then \[\cos \theta =\frac{{{a}_{1}}{{a}_{2}}+{{b}_{1}}{{b}_{2}}+{{c}_{1}}{{c}_{2}}}{\sqrt{a_{1}^{2}+b_{1}^{2}+c_{1}^{2}}\sqrt{a_{2}^{2}+b_{2}^{2}+c_{2}^{2}}}\] \[\Rightarrow \] \[\cos \theta =\frac{0-2\times 1+2\times 1}{\sqrt{0+1+4}\sqrt{16+4+1}}\] \[=\frac{0-2+2}{\sqrt{5}\sqrt{21}}=0\] \[\Rightarrow \] \[\theta =\frac{\pi }{2}\] \[\therefore \] \[\angle POQ=\frac{\pi }{2}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner