A) \[12\]
B) \[14\]
C) \[16\]
D) \[18\]
Correct Answer: C
Solution :
Given, \[|\vec{a}|=10,\,\,\,|\vec{b}|=2\]and \[\vec{a}\,.\,\vec{b}=12\] \[\Rightarrow \] \[|\vec{a}||\vec{b}|\,\cos \,\theta =12\] \[\Rightarrow \] \[10\times 2\times \cos \theta =12\Rightarrow \cos \theta =\frac{12}{20}=\frac{3}{5}\] \[\therefore \] \[\sin \theta =\sqrt{1-{{\cos }^{2}}\theta }=\sqrt{1-\frac{9}{25}}=\frac{4}{5}\] Now, \[|\vec{a}\times \vec{b}|=\,|\vec{a}|\,|\vec{b}|\,\sin \theta =10\times 2\times \frac{4}{5}=16\]
You need to login to perform this action.
You will be redirected in
3 sec
