J & K CET Engineering J and K - CET Engineering Solved Paper-2007

  • question_answer
    The specific conductance \[(\kappa )\] of an electrolyte of 0.1 N concentration is related to equivalent  \[(\Lambda )\]by the following formula

    A) \[A=\kappa \]

    B) \[A=10\,\kappa \]

    C)  \[A=100\,\kappa \]

    D) \[A=10,000\,\kappa \]

    Correct Answer: D

    Solution :

     Equivalent conductance \[(\wedge )\] = specific conductance \[(\kappa )\times o|\] where,\[o|=\]volume in\[c{{m}^{3}}\]containing 1 g equivalent of electrolyte 0.1 g equivalent is dissolve in \[=1000\text{ }c{{m}^{3}}\] 1 g equivalent is dissolve in \[=\frac{1000}{0.1}c{{m}^{3}}\] \[=10,000\,c{{m}^{3}}\] So, \[\wedge =10,000\,\kappa \]


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